document.write( "Question 1040474: PQRS is a parallelogram with PQ=2x cm, QR=x cm and angle PQR=110°. If the parallelogram have an area of 93.5304 cm², find the value of x. \n" ); document.write( "
Algebra.Com's Answer #655303 by ikleyn(52810)\"\" \"About 
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\n" ); document.write( "PQRS is a parallelogram with PQ=2x cm, QR=x cm and angle PQR=110°. If the parallelogram have an area of 93.5304 cm², find the value of x.
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document.write( "Area of a parallelogram is the product of the lengths of its two adjacent sides by the sine of the angle between them:\r\n" );
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document.write( "S = x*2x*sin(110°),   or\r\n" );
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document.write( "S = \"2x%5E2%2Asin%28110%5Eo%29\".\r\n" );
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document.write( "(See the lesson Area of a parallelogram in this site).\r\n" );
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document.write( "Notice that sin(110°) = sin(180°-110°) = sin(70°).\r\n" );
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document.write( "Therefore, S = \"2x%5E2%2Asin%2870%5Eo%29\".\r\n" );
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document.write( "Hence, x = \"sqrt%28S%2F%282%2Asin%2870%5Eo%29%29%29\" = \"sqrt%2893.5304%2F%282%2Asin%2870%5Eo%29%29%29%29\".\r\n" );
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document.write( "Now use your calculator and complete calculations.\r\n" );
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