document.write( "Question 1040393: Can I please have your assistance? If f(x) = 2x +1 and g(x) = x2, what is f o g? What is g o f? \n" ); document.write( "
Algebra.Com's Answer #655298 by Theo(13342)![]() ![]() You can put this solution on YOUR website! fog(x) = f(g(x)) \n" ); document.write( "gof(x) = g(f(x))\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f(x) = 2x+1 \n" ); document.write( "g(x) = x^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "fog(x) = f(g(x)) = f(x^2) = 2*(x^2) + 1. = 2x^2 + 1 \n" ); document.write( "you are simply replacing x in f(x) with g(x). \n" ); document.write( "x is the argument in f(x). \n" ); document.write( "g(x) is the argument in f(g(x)) \n" ); document.write( "since g(x) = x^2, then f(g(x)) becomes f(x^2) which becomes 2*(x^2) + 1 which becomes 2x^2 + 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "gof(x) = g(f(x)) = g(2x+1) = (2x+1)^2 = 4x^2 + 4x + 1 \n" ); document.write( "you are simply replacing x in g(x) with f(x). \n" ); document.write( "x is the argument in g(x). \n" ); document.write( "f(x) is the argument in g(f(x)) \n" ); document.write( "since f(x) = 2x+1, then g(f(x)) becomes g(2x+1) which becomes (2x+1)^2 which becomes 4x^2 + 4x + 1 \n" ); document.write( " |