document.write( "Question 1040483: I am having trouble with this question: \"What is the product of (y+2)(y-8)? The answers available are
\n" ); document.write( "y^2+6y-16 , y^2-6y-16 , y^2-6y+16 , y^2+6y+16 . Please explain how you got the correct answer, thank you so much in advance , Emily.
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Algebra.Com's Answer #655295 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
all you need to do is multiply the factors together.
\n" ); document.write( "you would use the distributive law of multiplication.
\n" ); document.write( "that law says:\r
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\n" ); document.write( "\n" ); document.write( "a * (b + c) =
\n" ); document.write( "(a*b) + (a*c)\r
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\n" ); document.write( "\n" ); document.write( "that law also says:\r
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\n" ); document.write( "\n" ); document.write( "(a + b) * (c + d) =
\n" ); document.write( "(a * (c + d)) + (b * (c + d)) =
\n" ); document.write( "(a*c) + (a*d) + (b*c) + (b*d).\r
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\n" ); document.write( "\n" ); document.write( "in other words, every term in the multiplier needs to multiply every term in the multiplicand exactly one time.\r
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\n" ); document.write( "\n" ); document.write( "this works for any number of terms.\r
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\n" ); document.write( "\n" ); document.write( "a more complex example would be:\r
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\n" ); document.write( "\n" ); document.write( "(a + b + c) * (d + e + f) =
\n" ); document.write( "(a * (d + e + f)) + (b * (d + e + f)) + (c * (d + e + f)) =
\n" ); document.write( "(a*d) + (a*e) + (a*f) + (b*d) + (b*e) + (b*f) + (c*d) + (c*e) + (c*f)\r
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\n" ); document.write( "\n" ); document.write( "in your problem:\r
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\n" ); document.write( "\n" ); document.write( "start with (y+2) * (y-8)
\n" ); document.write( "this becomes (y*(y-8)) + (2*(y-8))
\n" ); document.write( "which becomes (y*y) - (y*8) + (2*y) - (2*8)
\n" ); document.write( "simplify this to get y^2 - 8y + 2y - 16
\n" ); document.write( "combine like terms to get y^2 - 6y - 16\r
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\n" ); document.write( "\n" ); document.write( "i believe that is one of your selections.\r
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