document.write( "Question 1040399: A survey of 800 women shoppers found that 17% of them shop on impulse. What is the 98% confidence interval for the true proportion of women shoppers who shop on impulse?
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document.write( "A. 0.136 < p < 0.204
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document.write( "B. 0.139 < p < 0.201
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document.write( "C. 0.148 < p < 0.192
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document.write( "D. 0.144 < p < 0.196 \n" );
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Algebra.Com's Answer #655280 by jim_thompson5910(35256) ![]() You can put this solution on YOUR website! \n" ); document.write( "Use this table (or similar) to find that the critical z value is 2.326\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Look at the confidence level of 98% (bottom of page). Then look directly above it to find the value 2.326\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So z = 2.326\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Given information \n" ); document.write( "phat = 0.17 \n" ); document.write( "n = 800\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Standard Error: \n" ); document.write( "SE = sqrt(phat*(1-phat)/n) \n" ); document.write( "SE = sqrt(0.17*(1-0.17)/800) \n" ); document.write( "SE = 0.0132806249853\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Margin of error \n" ); document.write( "ME = z*SE \n" ); document.write( "ME = 2.326*0.0132806249853 \n" ); document.write( "ME = 0.0308907337158\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Lower Bound (L) of the confidence interval \n" ); document.write( "L = phat - ME \n" ); document.write( "L = 0.17 - 0.0308907337158 \n" ); document.write( "L = 0.1391092662842 \n" ); document.write( "L = 0.139\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Upper Bound (U) of the confidence interval \n" ); document.write( "U = phat + ME \n" ); document.write( "U = 0.17 + 0.0308907337158 \n" ); document.write( "U = 0.2008907337158 \n" ); document.write( "U = 0.201\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The confidence interal is (L,U) = (0.139, 0.201) which is equilavent to saying L < p < U which turns into 0.139 < p < 0.201\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the answer is choice B) 0.139 < p < 0.201\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The population proportion p is somewhere between 13.9% and 20.1% and we're 98% confident of this fact.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |