document.write( "Question 1040401: The Pizza Shop wanted to determine what proportion of its customers ordered only cheese pizza. Out of 80 customers surveyed, 15 ordered cheese pizza. What is the 99% confidence interval of the true proportion of customers who order only cheese pizza?
\n" ); document.write( "A. 0.115 < p < 0.260
\n" ); document.write( "B. 0.086 < p < 0.289
\n" ); document.write( "C. 0.075 < p < 0.300
\n" ); document.write( "D. 0.102 < p < 0.273
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Algebra.Com's Answer #655210 by Boreal(15235)\"\" \"About 
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1 sample proportion
\n" ); document.write( "p=15/80=0.1875
\n" ); document.write( "CI interval +/- is z(0.995) sqrt{p(1-p)/n}
\n" ); document.write( "2.576*sqrt{(0.1875)(0.8125)/80}; the second term is 0.0436
\n" ); document.write( "multiplied by 2.576 is 0.1124
\n" ); document.write( "CI is (0.0751,0.2999)
\n" ); document.write( "It is C.
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