document.write( "Question 1040368: Joey is twice as old as Glaiza while Priam is 24 years younger than Joey.If half of Joey's age six years ago was three less than one half the sum of Glaiza's age in four years and Priam's present age,find the ages of each.
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Algebra.Com's Answer #655197 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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\n" ); document.write( "Let j = Joe's age
\n" ); document.write( "let g = Glaze's age
\n" ); document.write( "let p = Prim's age
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statment
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\n" ); document.write( "Joey is twice as old as Glaiza
\n" ); document.write( "j = 2g
\n" ); document.write( "or
\n" ); document.write( "g = .5j
\n" ); document.write( " while Priam is 24 years younger than Joey.
\n" ); document.write( "p = j - 24\r
\n" ); document.write( "\n" ); document.write( "If half of Joey's age six years ago was three less than one half the sum of Glaiza's age in four years and Priam's present age,
\n" ); document.write( " $\"1%2F2\"$ (j-6) = $\"1%2F2\"$ ((g+4) + p) - 3
\n" ); document.write( "multiply both sides by 2 to get rid of the fractions
\n" ); document.write( "j - 6 = (g+4) + p - 2(3)
\n" ); document.write( "j - 6 = g + p + 4 - 6
\n" ); document.write( "Add 6 to both sides
\n" ); document.write( "j = g + p + 4
\n" ); document.write( "Replace g with .5j; replace p with (j-24)
\n" ); document.write( "j = .5j + (j-24) + 4
\n" ); document.write( "j -.5j - j = - 24 + 4
\n" ); document.write( "-.5j = -20
\n" ); document.write( "j = -20/-.5
\n" ); document.write( "j = +40 yrs is Joe's age
\n" ); document.write( "then
\n" ); document.write( "p = 40 - 24
\n" ); document.write( "p = 16 yrs is Prim's age
\n" ); document.write( "and
\n" ); document.write( "g = .5(40)
\n" ); document.write( "g = 20 yrs is Glaze's age \n" ); document.write( "

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