document.write( "Question 1040378: I'm having some trouble w/ this problem and could use some help please:\r
\n" ); document.write( "\n" ); document.write( "I need to express log x + log 1 – 4 log y as an equivalent expression. I come up with log(x+1-4y)\r
\n" ); document.write( "\n" ); document.write( "I feel like I'm doing something wrong here. I would really appreciate some help, thank you!
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Algebra.Com's Answer #655193 by ikleyn(52794)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "  log(x) + log(1) – 4*log(y) = \r\n" );
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document.write( "= log(x) +   0    - 4*log(y) =\r\n" );
document.write( "= \"log%28%28x%2Fy%5E4%29%29\".\r\n" );
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On properties of logarithms see the lessons\r
\n" ); document.write( "\n" ); document.write( "    - WHAT IS the logarithm, \r
\n" ); document.write( "\n" ); document.write( "    - Properties of the logarithm, \r
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