document.write( "Question 1040358: If x = 2015, y = 2014 and z = 2013, then the value of
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Algebra.Com's Answer #655172 by ikleyn(52778) $\"\"$ $\"About$

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\n" ); document.write( "If x = 2015, y = 2014 and z = 2013, then the value of
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document.write( "    = \r\n" );
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document.write( "=  = \r\n" );
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document.write( "=  = \r\n" );
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document.write( "= 2015*1 + 2014*1 + 2013*(-2) =  2015 + 2014 - 2*2013 = (2015-2013) + (2014-2013) = 3.\r\n" );
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\n" ); document.write( "\n" ); document.write( "The right and more effective question would be \"calculate without a calculator\".\r
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