document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1040349>Question 1040349</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many items are in each box if 900 items are divided: among three boxes such that the first box contains half of the second box while the third box contains thrice of the first box? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #655166 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=655166\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the amount in the first box.\r<BR>\n" );
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document.write( "then 2x is the amount in the second box, and 3x is the amount in the third box.\r<BR>\n" );
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document.write( "the first box contains half of the second box because x is 1/2 of 2x.\r<BR>\n" );
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document.write( "the third box contains three times the first box because 3x is 3 times x.\r<BR>\n" );
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document.write( "the requirements of the problem statement are satisfied.\r<BR>\n" );
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document.write( "the sum of all of the amounts in each box is therefore x + 2x + 3x = 6x.\r<BR>\n" );
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document.write( "since the total of the amount in all 3 boxes is 900, your equation becomes 6x = 900\r<BR>\n" );
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document.write( "divide both sides of this equation by 6 to get x = 900/6 = 150.\r<BR>\n" );
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document.write( "the first box contains x which is equal to 150.<BR>\n" );
document.write( "the second box contains 2x which is equal to 300.<BR>\n" );
document.write( "the third box contains 3x which is equal to 450.\r<BR>\n" );
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document.write( "add them up and you have a total of 900.\r<BR>\n" );
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