document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1040336>Question 1040336</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 46 feet. The length is 5 feet more than the width. Find the dimensions </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #655142 by </B><A HREF=/tutors/aboutme.mpl?userid=Aldorozos><B>Aldorozos(172)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Aldorozos><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=655142\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = length<BR>\n" );
document.write( "W = width\r<BR>\n" );
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document.write( "L = W +5\r<BR>\n" );
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document.write( "Perimeter = 46 = 2(L+W) = 2(W+W+5) =2(2W+5)\r<BR>\n" );
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document.write( "46 = 2(2w+5) Dividing both sides by 2 we get 23 = 2W+ 5 <BR>\n" );
document.write( "Therefore 18 = 2W which means W =9<BR>\n" );
document.write( "If W = 9 then L = 9+5 = 14 </SPAN>\n" );
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