document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1040299>Question 1040299</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. Please help me to solve this? (2a - 3b) ( a + 12b)<BR>\n" );
document.write( "2.  Please help me to solve this? (-m + 6n ) ( -3m - 7n)<BR>\n" );
document.write( "3. Please help me to solve this? (-4p - q) ( 2p + 9q)<BR>\n" );
document.write( "4. Please help me to solve this? -3(h - 11) (5h - 5) <BR>\n" );
document.write( "5. Please help me to solve this [( x + 3) + 2 ] [( x + 3) - 5]<BR>\n" );
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document.write( "Thank you in advance </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #655121 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=655121\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiply each term in the first by each term in the second.  There are four terms.<BR>\n" );
document.write( "For the first, it would be 2a*2+2a(12b)-3b(a)-3b(12b)=2a^2-3ab+24ab-36b^2<BR>\n" );
document.write( "That is 2a^2+21ab-36b^2. Remember, ab and ba are the same.<BR>\n" );
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document.write( "The second is 3m^2-11mn-42n^2.<BR>\n" );
document.write( "(-m+6n)(-3m-7n)=(-m)(-3m)+(-m)(-7n)+(6n)(-3m)+(6n)(-7n)=3m^2+7mn-18mn-42n^2.  There are four terms from a 2 x 2 binomial.  Each term in the first is multiplied by each term in the second.  There will be a m^2 and n^2 and two mn terms.  The others are done the same way.<BR>\n" );
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document.write( "The third is -8p^2-38pq-9q^2<BR>\n" );
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document.write( "The fourth is done by putting the -3 in last.  (5h^2-60h+55), so it becomes -15h^2+180h-165<BR>\n" );
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document.write( "The fifth is (x+5)(x-2), because the parentheses don't change anything when there is addition.  We can add in any order we choose.<BR>\n" );
document.write( "That is foiled out to x^2+3x-10.<BR>\n" );
document.write( "The long way is (x+3)^2-5(x+3)+2(x=3)-10<BR>\n" );
document.write( "That is (x+3)^2-3(x+3)-10<BR>\n" );
document.write( "That is x^2+6x+9-3x-9-10<BR>\n" );
document.write( "That is x^2+3x-10 </SPAN>\n" );
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