document.write( "Question 90277: Graph f(x) = –x – 2. \n" ); document.write( "
Algebra.Com's Answer #65512 by jim_thompson5910(35256)\"\" \"About 
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Solved by pluggable solver: Graphing Linear Equations
In order to graph \"y=-1%2Ax-2\" we only need to plug in two points to draw the line
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\n" ); document.write( " So lets plug in some points
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\n" ); document.write( " Plug in x=-9
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\n" ); document.write( " \"y=-1%2A%28-9%29-2\"
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\n" ); document.write( " \"y=9-2\" Multiply
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\n" ); document.write( " \"y=7\" Add
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\n" ); document.write( " So here's one point (-9,7)
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\n" ); document.write( " Now lets find another point
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\n" ); document.write( " Plug in x=-8
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\n" ); document.write( " \"y=-1%2A%28-8%29-2\"
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\n" ); document.write( " \"y=8-2\" Multiply
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\n" ); document.write( " \"y=6\" Add
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\n" ); document.write( " So here's another point (-8,6). Add this to our graph
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\n" ); document.write( " Now draw a line through these points
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\n" ); document.write( " So this is the graph of \"y=-1%2Ax-2\" through the points (-9,7) and (-8,6)
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\n" ); document.write( " So from the graph we can see that the slope is \"-1%2F1\" (which tells us that in order to go from point to point we have to start at one point and go down -1 units and to the right 1 units to get to the next point), the y-intercept is (0,\"-2\")and the x-intercept is (\"-2\",0)
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\n" ); document.write( " We could graph this equation another way. Since \"b=-2\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"-2\").
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\n" ); document.write( " So we have one point (0,\"-2\")
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\n" ); document.write( " Now since the slope is \"-1%2F1\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"-2\"), we can go down 1 units
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\n" ); document.write( " and to the right 1 units to get to our next point
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\n" ); document.write( " Now draw a line through those points to graph \"y=-1%2Ax-2\"
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\n" ); document.write( " So this is the graph of \"y=-1%2Ax-2\" through the points (0,-2) and (1,-3)
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