document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1040321>Question 1040321</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given csc theta = (2 sqr3)/(3) and -270 less than 0 less than 180<BR>\n" );
document.write( "determine the exact values of theta\r<BR>\n" );
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document.write( "my work:\r<BR>\n" );
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document.write( "(2 sqr3)/3 = 1/sin theta<BR>\n" );
document.write( "sin theta * (2sqr3)/3 =1<BR>\n" );
document.write( "sin theta = 1/ (2sqr3/3)<BR>\n" );
document.write( "sin theta = 3/ (2sqr3)<BR>\n" );
document.write( "when I try to find the inverse of sin theta to find the angle, it gives me an error </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #655116 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=655116\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I would go the other way<BR>\n" );
document.write( "csc=2 sqrt(3)/3 is 2/sqrt(3)<BR>\n" );
document.write( "Therefore the sin is sqrt (3)/2<BR>\n" );
document.write( "That occurs at pi/3 and 2pi/3  on the interval 0 to 2 pi (which covers the above.<BR>\n" );
document.write( "With the calculator, try entering 3/(2sqrt(3))<BR>\n" );
document.write( "You should get 0.8660.<BR>\n" );
document.write( "if you enter 3/2 sqrt(3), the calculator will make that 1.5 *sqrt(3), and you can't take the arc sin of it, because it is greater than 1.\r<BR>\n" );
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