document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1040292>Question 1040292</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If m<2 = x/2 -10 and m<3= x/3 + 40, find x and m<2 <BR>\n" );
document.write( "Note: these angles are supplementary  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #655106 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=655106\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  If m<2 = x/2 -10 and m<3= x/3 + 40, find x and m<2 <BR>\n" );
document.write( "Note: these angles are supplementary <BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Eq::<BR>\n" );
document.write( "(x/2-10) + (x/3+40) = 180 degrees<BR>\n" );
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document.write( "(5/6)x + 30 = 180<BR>\n" );
document.write( "----<BR>\n" );
document.write( "x = 6/5 * 150<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "x = 180<BR>\n" );
document.write( "----<BR>\n" );
document.write( "m<2 =(x/2) - 10 = 180/2 - 10 = 80 degrees<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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