document.write( "Question 1040310: Olivia traveled 25 miles in 30 minutes, and then she traveled for an additional
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document.write( "20 minutes. If her average speed for the entire trip was 36 miles per hour
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document.write( "(mph), what was her average speed for the final 20 minutes of the trip?
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Algebra.Com's Answer #655101 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Olivia traveled 25 miles in 30 minutes, and then she traveled for an additional \n" ); document.write( "20 minutes. If her average speed for the entire trip was 36 miles per hour \n" ); document.write( "(mph), what was her average speed for the final 20 minutes of the trip? \n" ); document.write( "------------------- \n" ); document.write( "1st leg DATA:: dist = 25 miles ; time = 30 min = (1/2) hour \n" ); document.write( "------------- \n" ); document.write( "2nd leg DATA:: dist = x miles ; time = (1/3) hour \n" ); document.write( "------------------------------------------------- \n" ); document.write( "Average speed = total distance / total time = (25+x)/(5/6 hour) = 30 + (6/5)x mph \n" ); document.write( "------ \n" ); document.write( " Equation: \n" ); document.write( "(20 + (6/5)x) mph = 36 mph \n" ); document.write( "(6/5)x = 16 \n" ); document.write( "x = 80/6 miles (2nd leg distance) \n" ); document.write( "----- \n" ); document.write( "Ans: 2nd leg speed = dist/time = (80/6)/(1/5) = 400/6 = 66 2/3 mph \n" ); document.write( "------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |