document.write( "Question 90005: Jennifer has nickels and quarters. If Jennifer had seven more nickels and four times the number of quarters she would have $22.85 more. How much money she have? \n" ); document.write( "
Algebra.Com's Answer #65510 by ankor@dixie-net.com(22740)\"\" \"About 
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Jennifer has nickels and quarters. If Jennifer had seven more nickels and four times the number of quarters she would have $22.85 more. How much money she have?
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\n" ); document.write( "Let x = amt of money she has; n = no. of nickels; q = no. of quarters
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\n" ); document.write( "The basic equation:
\n" ); document.write( ".05n + .25q = x
\n" ); document.write( ":
\n" ); document.write( "\"seven more nickels and four times the number of quarters she would have $22.85 more.\"
\n" ); document.write( ".05(n+7) + .25(4q) = (x+22.85)
\n" ); document.write( ".05n + .35 + 1.00q = x + 22.85
\n" ); document.write( ".05n + 1.0q = x + 22.85 - .35
\n" ); document.write( ".05n + 1.0q = x + 22.50
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\n" ); document.write( "Subtract the basic equation from the the above equation, find q:
\n" ); document.write( ".05n + 1.0q = x + 22.50
\n" ); document.write( ".05n + .25q = x
\n" ); document.write( "-------------------------subtract, eliminates n and x
\n" ); document.write( "0n + .75q = 0x + 22.50
\n" ); document.write( ".75q = 22.50
\n" ); document.write( "q = 22.50/.75
\n" ); document.write( "q = 30 quarters originally
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\n" ); document.write( "At this point it is apparent that there is no unique solutions for n and x.
\n" ); document.write( "although they are dependent on each other:
\n" ); document.write( "using equation .05n + 1.0q = x + 22.50
\n" ); document.write( ".05n + 1(30) = x + 22.50
\n" ); document.write( ".05n + 30 = x + 22.50
\n" ); document.write( ".05n = x + 22.50 - 30
\n" ); document.write( ".05n = x - 7.50
\n" ); document.write( ":
\n" ); document.write( "We know that x has to be greater than 7.50 and multiple of .05
\n" ); document.write( "For example, let x = 8
\n" ); document.write( ".05n = 8 - 7.50
\n" ); document.write( "n = .50/.05
\n" ); document.write( "n = 10 nickels
\n" ); document.write( ":
\n" ); document.write( "Let x = 20
\n" ); document.write( ".05n = 20 - 7.50
\n" ); document.write( "n = 12.50/.05
\n" ); document.write( "n = 250 nickels
\n" ); document.write( ":
\n" ); document.write( "Either one will satisfy the equation, try: x = 20, n = 250:
\n" ); document.write( ".05(250+7) + .25(4*30) = 20 + 22.85
\n" ); document.write( ".05(257) + .25(120) = 42.85
\n" ); document.write( " 12.85 + 30 = 42.85
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\n" ); document.write( "Does this help?
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