document.write( "Question 1040264: A rectangle is
\n" ); document.write( "4 times as long as it is wide. The perimeter is
\n" ); document.write( "50 feet. Find the dimensions
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Algebra.Com's Answer #655053 by addingup(3677)\"\" \"About 
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L = 4W
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\n" ); document.write( "2L+2W = 50
\n" ); document.write( "Substitute for L:
\n" ); document.write( "2(4w)+2W = 50
\n" ); document.write( "8W+2W = 50
\n" ); document.write( "10W = 50
\n" ); document.write( "W= 5 and L = 4(5) = 20
\n" ); document.write( "Check:
\n" ); document.write( "2(5)+2(20) = 50 Correct.
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