document.write( "Question 1040264: A rectangle is
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document.write( "4 times as long as it is wide. The perimeter is
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document.write( "50 feet. Find the dimensions \n" );
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Algebra.Com's Answer #655053 by addingup(3677)![]() ![]() You can put this solution on YOUR website! L = 4W \n" ); document.write( "and \n" ); document.write( "2L+2W = 50 \n" ); document.write( "Substitute for L: \n" ); document.write( "2(4w)+2W = 50 \n" ); document.write( "8W+2W = 50 \n" ); document.write( "10W = 50 \n" ); document.write( "W= 5 and L = 4(5) = 20 \n" ); document.write( "Check: \n" ); document.write( "2(5)+2(20) = 50 Correct. \n" ); document.write( ": \n" ); document.write( "John \n" ); document.write( " |