document.write( "Question 1040248:
\n" ); document.write( "A landscaper plans to dig a rectangular garden whose length is to be
\n" ); document.write( "2feet more than the width. If the landscaper has 36 feet of fencing to enclose the​ garden, what should be the dimensions of the​ garden?\r
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\n" ); document.write( "\n" ); document.write( "What is the​ width? in feet. _____
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Algebra.Com's Answer #655030 by Aldorozos(172)\"\" \"About 
You can put this solution on YOUR website!
Let's assume W = width and L = Length, We know that L = W + 2
\n" ); document.write( "We also know that 2(W+L) = perimeter of the rectangle = 36\r
\n" ); document.write( "\n" ); document.write( "2(W+L) = 2(W+ W+2) = 36
\n" ); document.write( "Therefore 2(2W+2) = 36
\n" ); document.write( "Dividing both sides by 2 we get
\n" ); document.write( "2W+2 = 18
\n" ); document.write( "2W = 16
\n" ); document.write( "W = 16/2 = 8
\n" ); document.write( "Considering that L = W+2 we get Length = 8+2 = 10
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