document.write( "Question 1040238: Jane is saving money to buy a laptop computer costing $1200. Jane models her savings by the equation, y=360+120x, where x is the number of consecutive monthly deposits and y is the balance in the account. If Jane makes her first deposit in January 2010 and continues making deposits each month thereafter, in what month and year will she be able to buy her laptop? \n" ); document.write( "

Algebra.Com's Answer #655026 by josmiceli(19441) $\"\"$ $\"About$

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You want to know when the balance in her account
\n" ); document.write( "reaches $1200, so
\n" ); document.write( " $\"+1200+=+360+%2B+120x+\"$
\n" ); document.write( " $\"+120x+=+840+\"$
\n" ); document.write( " $\"+x+=+7+\"$
\n" ); document.write( "There are 7 consecutive monthly deposits
\n" ); document.write( "She can buy laptop 6 months after the 1st deposit
\n" ); document.write( "in Jan 2010.
\n" ); document.write( "That is July 2010 \n" ); document.write( "

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