document.write( "Question 90245: Use the Intermediate Value Theorem to determine if P(x) = 2x^5 - 7x +1 has a zero in the intervals [1,2]. \n" ); document.write( "
Algebra.Com's Answer #65500 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's evaluate \"f%281%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=2x%5E5-7x%2B1\" Start with the given polynomial\r
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\n" ); document.write( "\n" ); document.write( "\"f%281%29=2%281%29%5E5-7%281%29%2B1\" Plug in \"x=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%281%29=2%281%29-7%281%29%2B1\" Raise 1 to the fifth power to get 1\r
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\n" ); document.write( "\n" ); document.write( "\"f%281%29=2-7%281%29%2B1\" Multiply 2 by 1 to get 2\r
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\n" ); document.write( "\n" ); document.write( "\"f%281%29=2-7%2B1\" Multiply 7 by 1 to get 7\r
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\n" ); document.write( "\n" ); document.write( "\"f%281%29=-4\" Now combine like terms\r
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\n" ); document.write( "\n" ); document.write( "Now let's evaluate \"f%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=2x%5E5-7x%2B1\" Start with the given polynomial\r
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\n" ); document.write( "\n" ); document.write( "\"f%282%29=2%282%29%5E5-7%282%29%2B1\" Plug in \"x=2\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%282%29=2%2832%29-7%282%29%2B1\" Raise 2 to the fifth power to get 32\r
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\n" ); document.write( "\n" ); document.write( "\"f%282%29=64-7%282%29%2B1\" Multiply 2 by 32 to get 64\r
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\n" ); document.write( "\n" ); document.write( "\"f%282%29=64-14%2B1\" Multiply 7 by 2 to get 14\r
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\n" ); document.write( "\n" ); document.write( "\"f%282%29=51\" Now combine like terms\r
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\n" ); document.write( "\n" ); document.write( "Since our y-value changes from a negative value to a positive value in the interval [1,2] this means there is a zero in this interval.
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