document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1820>Question 1820</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, how do i graph the equation 2x+3y=6. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #655 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=655\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> any straight line can be sketched if you know it in the form y = mx + c where m is the gradient and c in the y-intercept...so we need to re-arrange your equation slightly\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%2B3y=6 ALIGN=MIDDLE  ALT=\"2x%2B3y=6\"   DISABLED_style= \"max-width:90%; height:auto;\" > becomes <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3y+=+-2x+%2B+6 ALIGN=MIDDLE  ALT=\"3y+=+-2x+%2B+6\"   DISABLED_style= \"max-width:90%; height:auto;\" > then becomes <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%28-2x+%2B+6%29%2F3 ALIGN=MIDDLE  ALT=\"y+=+%28-2x+%2B+6%29%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > which is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+%28-2%2F3%29x+%2B+2 ALIGN=MIDDLE  ALT=\"y+=+%28-2%2F3%29x+%2B+2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "so, the gradient is -2/3 and the y-intercept is at y=2\r<BR>\n" );
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document.write( "We can also find where the line crosses the x-axis, as this is where y=0, so putting y=0 into the equation (any version) gives x=3.\r<BR>\n" );
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document.write( "You need to know what a +ve and -ve gradient looks like:\r<BR>\n" );
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document.write( "+ve is /<BR>\n" );
document.write( "-ve is \\r<BR>\n" );
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document.write( "cheers<BR>\n" );
document.write( "Jon<BR>\n" );
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