document.write( "Question 1040199: Present age of vanilla is four times the present age of her sister mala. After 10years, twice vani's age will be four times males age. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #654999 by ikleyn(52908)\"\" \"About 
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\n" ); document.write( "Present age of vanilla is four times the present age of her sister mala.
\n" ); document.write( "After 10 years, twice vani's age will be four times males age. Find their present ages.
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document.write( "V       = 4A         (1)      (Present age . . . )\r\n" );
document.write( "2(V+10) = 4(A+10)    (2)      (After 10 years . . . )\r\n" );
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document.write( "Divide (2) by 2 (both sides) and substitute V from (1) into (2). You will get\r\n" );
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document.write( "4A + 10 = 2(A+10),\r\n" );
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document.write( "4A + 10 = 2A + 20,\r\n" );
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document.write( "2A = 20 - 10,\r\n" );
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document.write( "2A = 10,\r\n" );
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document.write( "A = 5.\r\n" );
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document.write( "Hence, V = 4A = 4*5 = 20.\r\n" );
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document.write( "Answer.  A is 5, V is 20.\r\n" );
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