document.write( "Question 1040168: Joan Arlington has twice as much money invested at 5% simple annual interest as she does at 4%. If her yearly income from the two investments is $357, how much does she have at each rate? \n" ); document.write( "

Algebra.Com's Answer #654987 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = amount invested at 4%
\n" ); document.write( " $\"+2x+\"$ = amount invested at 5%
\n" ); document.write( "---------------------------------
\n" ); document.write( " $\"+.04x+%2B+.05%2A%282x%29+=+357+\"$
\n" ); document.write( " $\"+.04x+%2B+.1x+=+357+\"$
\n" ); document.write( " $\"+.14x+=+357+\"$
\n" ); document.write( " $\"+x+=+2550+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+2x+=+5100+\"$
\n" ); document.write( "The amount invested at 4% is $2,550
\n" ); document.write( "The amount invested at 5% is $5,100
\n" ); document.write( "-----------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+.04x+%2B+.1x+=+357+\"$
\n" ); document.write( " $\"+.04%2A2550+%2B+.1%2A2550+=+357+\"$
\n" ); document.write( " $\"+102+%2B+255+=+357+\"$
\n" ); document.write( " $\"+357+=+357+\"$
\n" ); document.write( "OK \n" ); document.write( "

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