document.write( "Question 1040131: jimmy invest 16000 in an account that pays 8.13% compounded quarterly. How long(in years and months) will it take for his investment to reach 21000. Round the answer for months up to the nearest multiple of 3 \n" ); document.write( "
Algebra.Com's Answer #654942 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! jimmy invest 16000 in an account that pays 8.13% compounded quarterly. \n" ); document.write( " How long(in years and months) will it take for his investment to reach 21000. \n" ); document.write( ": \n" ); document.write( "the compound interest formula \n" ); document.write( " \n" ); document.write( "A = the resulting amt after t yrs \n" ); document.write( "P = initial amt \n" ); document.write( "r = annual interest rate in decimal form \n" ); document.write( "n = compounding periods per yr \n" ); document.write( "t = no. of yrs \n" ); document.write( ": \n" ); document.write( "In the problem \n" ); document.write( "A = 21000 \n" ); document.write( "p = 16000 \n" ); document.write( "n = 4 (time per yr) \n" ); document.write( "r = .0813 \n" ); document.write( "t = yrs \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Using logs \n" ); document.write( " \n" ); document.write( "log equiv of exponents \n" ); document.write( "4t*log(1.020325) = log(1.3125) \n" ); document.write( "4t = \n" ); document.write( "use you calc \n" ); document.write( "4t = 13.515 \n" ); document.write( "divide by 4 \n" ); document.write( "t = 3.379 yrs \n" ); document.write( "find the no. of months \n" ); document.write( ".379(12) = 4.54 months \n" ); document.write( "Rounds up to 4 yrs 9 months \n" ); document.write( " |