document.write( "Question 1040131: jimmy invest 16000 in an account that pays 8.13% compounded quarterly. How long(in years and months) will it take for his investment to reach 21000. Round the answer for months up to the nearest multiple of 3 \n" ); document.write( "
Algebra.Com's Answer #654942 by ankor@dixie-net.com(22740)\"\" \"About 
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jimmy invest 16000 in an account that pays 8.13% compounded quarterly.
\n" ); document.write( " How long(in years and months) will it take for his investment to reach 21000.
\n" ); document.write( ":
\n" ); document.write( "the compound interest formula
\n" ); document.write( "\"A+=+p%281+%2B+%28r%2Fn%29%29%5E%28nt%29\", where
\n" ); document.write( "A = the resulting amt after t yrs
\n" ); document.write( "P = initial amt
\n" ); document.write( "r = annual interest rate in decimal form
\n" ); document.write( "n = compounding periods per yr
\n" ); document.write( "t = no. of yrs
\n" ); document.write( ":
\n" ); document.write( "In the problem
\n" ); document.write( "A = 21000
\n" ); document.write( "p = 16000
\n" ); document.write( "n = 4 (time per yr)
\n" ); document.write( "r = .0813
\n" ); document.write( "t = yrs
\n" ); document.write( ":
\n" ); document.write( "\"16000%281+%2B+%28.0813%2F4%29%29%5E%284t%29\" = 21000
\n" ); document.write( "\"16000%281.020325%29%5E%284t%29\" = 21000
\n" ); document.write( "\"%281.020325%29%5E%284t%29\" = \"21000%2F16000%29%0D%0A%7B%7B%7B%281.020325%29%5E%284t%29\" = 1.3125
\n" ); document.write( "Using logs
\n" ); document.write( "\"log%281.020325%29%5E%284t%29\" = log(1.3125)
\n" ); document.write( "log equiv of exponents
\n" ); document.write( "4t*log(1.020325) = log(1.3125)
\n" ); document.write( "4t = \"log1.3125%2Flog%281.020325%29\"
\n" ); document.write( "use you calc
\n" ); document.write( "4t = 13.515
\n" ); document.write( "divide by 4
\n" ); document.write( "t = 3.379 yrs
\n" ); document.write( "find the no. of months
\n" ); document.write( ".379(12) = 4.54 months
\n" ); document.write( "Rounds up to 4 yrs 9 months
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