document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=13019>Question 13019</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two times anumber t decreased by eight equals seventy<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6549 by </B><A HREF=/tutors/aboutme.mpl?userid=pwac><B>pwac(253)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pwac><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6549\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is written as an equation:-<BR>\n" );
document.write( "2t-8=70 It needs to be re-arranged to find value of t.First add 8 to both sides<BR>\n" );
document.write( "2t=78 Divide both sides by 2<BR>\n" );
document.write( "t=78/2<BR>\n" );
document.write( "t=39.<BR>\n" );
document.write( "Check by putting this value into original equation<BR>\n" );
document.write( "2X39 -8 = 70<BR>\n" );
document.write( "78-8 is 70<BR>\n" );
document.write( "Pete </SPAN>\n" );
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