document.write( "Question 1039820: Suppose the chance of rain for each of the next three days is 50%, You are planning an outdoor activity and want to estimate the chance that it will not rain at least one of the days. A coin was used to similate the weather each day. There was obtained 20 sets of three days (R for rain) means that there was a rain in the given day and (s for sunny means that there wasn't rain. Row one had 9 R and 11 S, row two has 11 R and 9 S, and row three has 11 R and 9 S. What is the experimental probability that it will not rain at least one of the three days? \n" ); document.write( "
Algebra.Com's Answer #654895 by Theo(13342) You can put this solution on YOUR website! you have 3 sets of data of 20 sample points each. \n" ); document.write( "each set represents 1 of the 3 days.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the data tells you the following:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "day sunny rain total p(rain)\r\n" ); document.write( "1 11 9 20 9/20\r\n" ); document.write( "2 9 11 20 11/20\r\n" ); document.write( "3 9 11 20 11/20\r\n" ); document.write( "\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the experimental probability that it will rain on all 3 days is 9/20 * 11/20 * 11/20 = .136125\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the experimental probability that it will not rain on at least 1 of those days = 1 minus the probability that it will rain on all 3 of those days which is equal to 1 - .136125 = .863875.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "my interpretation of this problem is that each day had 20 coin flips to determine the probability that it would be sunny on that day or rainy on that day.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the results were based on that interpretation.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |