document.write( "Question 90230: Angela needs 20 quarts of 50% antifreeze solution in her radiator. She plans to obtain this by mixing some pure antifreeze with an appropriate amount of a 40% antifreeze solution. How many quarts of each should she use? \n" ); document.write( "

Algebra.Com's Answer #65487 by Nate(3500) $\"\"$ $\"About$

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$\"%281.00%28x%29+%2B+0.40%2820+-+x%29%29%2F%2820%29+=+0.50\"$
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\n" ); document.write( " $\"%28x+%2B+0.4%2820+-+x%29%29%2F%2820%29+=+0.5\"$
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\n" ); document.write( " $\"x+%2B+0.4%2820+-+x%29+=+10\"$
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\n" ); document.write( " $\"x+%2B+8+-+0.4x+=+10\"$
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\n" ); document.write( " $\"0.6x+=+2\"$
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\n" ); document.write( " $\"x+=+10%2F3\"$ or pure antifreeze
\n" ); document.write( " $\"20+-+10%2F3\"$ or $\"50%2F3\"$ of 40% antifreeze \n" ); document.write( "

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