document.write( "Question 1039987: x+y+z=12;xy+yz+zx=44;x^3+y^3+z^3=288. Find value of x,y and z. \n" ); document.write( "
Algebra.Com's Answer #654786 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! One way to do this is to note that for positive integers, which the answer must contain, the largest must be 6, because any larger would have a negative result for the other two. 6^3 is 216, and that leaves 72. That is the sum of two cubes, 64 (4^3) and 8 (2^3). \n" ); document.write( "6+4+2=12 \n" ); document.write( "24+8+12=44. \n" ); document.write( "In number theory a number not in the form of 9k+/-4 can be written as the sum of 3 cubes. \n" ); document.write( "That is as far as I can go. \n" ); document.write( " |