document.write( "Question 1039996: four boys are playing tug of war. The two boys on one side are pulling with forces of 80 N and 70 N. If the forces of the two boys on the other side are such that one is double the other, what is the resultant force? \n" ); document.write( "

Algebra.Com's Answer #654773 by Edwin McCravy(20066) $\"\"$ $\"About$

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four boys are playing tug of war. The two boys on one side are
\n" ); document.write( "pulling with forces of 80 N and 70 N. If the forces of the two
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document.write( "That would depend on whether the rope is moving.\r\n" );
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document.write( "If we assume that the rope is not moving, then the resultant \r\n" );
document.write( "force on the rope is 0.  \r\n" );
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document.write( "Is this a trick question?\r\n" );
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document.write( "Maybe you're asking for the tension in the rope if the rope is\r\n" );
document.write( "not moving.\r\n" );
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document.write( "In that case, the tension is the sum of the forces on each side,\r\n" );
document.write( "so it's 80N+70N=150N on each side, so the tension in the rope is\r\n" );
document.write( "twice that or 300N.\r\n" );
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document.write( "Maybe you want to know what forces the boys on the other side are\r\n" );
document.write( "pulling at.  If so, then:\r\n" );
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document.write( "   x + 2x = 150N\r\n" );
document.write( "       3x = 150N\r\n" );
document.write( "        x = 50N\r\n" );
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document.write( "So one boy is pulling at 50N and the other twice that at 100N. \r\n" );
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document.write( "It is not clear what you are asking.  Maybe it really is a trick\r\n" );
document.write( "question and the resulting force is 0, since the forces in\r\n" );
document.write( "opposite directions cancel each other out.\r\n" );
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document.write( "Edwin

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