document.write( "Question 1039984: I'm having a hard time w/ this and could really use some help please!:\r
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document.write( "For \"a\" am I multiplying the denominator to get rid of it and coming up w/ something like f^-1(y)= (x-something?). I'm not sure there.\r
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document.write( "Let f(x)=(6 - x)/(3 + 4x) \r
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document.write( "(a) Find f^-1 , the inverse function of f. Show work.\r
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document.write( "(b) What is the domain of f ? What is the domain of the inverse function?\r
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document.write( "(c) What is f(3) ? f (3) = _1/5___ \r
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document.write( "(d) What is f^-1 ( ____ ), where the number in the blank is your answer from part (c)? \r
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document.write( "I\"m getting really stressed and could use some help please. Thank you!
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Algebra.Com's Answer #654766 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! f(x)=(6-x)/(3+4x) \n" ); document.write( "x=(6-y)/(3+4y), interchange x and y \n" ); document.write( "3x+4xy=6-y \n" ); document.write( "y+4xy=6-3x \n" ); document.write( "y(1+4x)=6-3x \n" ); document.write( "y=f inv (x)=(6-3x)/(1+4x) \n" ); document.write( "domain of original function is all x except -(1/4) \n" ); document.write( "domain of inverse function is all x except x=(-1/4) \n" ); document.write( "f(3)=3/15=1/5 \n" ); document.write( "f inv (1/5)=(6-3/5)/(1+4/5) \n" ); document.write( "This is 27/5/9/5, or 3. \n" ); document.write( "Notice how it gives the original f(3) result back. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |