document.write( "Question 1039974: Can you help me to our assignment?
\n" ); document.write( " solve for b in terms of the other variable:
\n" ); document.write( " a/b+c + d/b-c=2/b+c
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Algebra.Com's Answer #654746 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
If grouping symbols are not missing or not needed, then you have equation \"a%2Fb%2Bc+%2B+d%2Fb-c=2%2Fb%2Bc\". The common denominator would be \"b\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28a%2Fb%2Bc+%2B+d%2Fb-c%29b=%282%2Fb%2Bc%29b\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%2Bbc%2Bd-bc=2%2Bbc\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%2Bd=2%2Bbc\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%2Bd-2=bc\"\r
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\n" ); document.write( "\n" ); document.write( "\"b=%28a%2Bd-2%29%2Fc\"\r
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\n" ); document.write( "\n" ); document.write( "In case that is not what you expect, then express your equation precisely.
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