document.write( "Question 1039967: Solve additional equation..
\n" ); document.write( "1.(-2m-2)/(3)+(2m-3)/(6)=(m)/(8)
\n" ); document.write( "2.(1)/(x)-(2)/(x+1)=(3)/(6x)
\n" ); document.write( "3.(9)/(7x-6)=(6)/(2-5x)
\n" ); document.write( "4.(3)/((x+1)^2)=-2
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Algebra.Com's Answer #654743 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"%283%29%2F%28%28x%2B1%29%5E2%29=-2\"\r
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\n" ); document.write( "\n" ); document.write( "You need to accept \"i%5E2=-1\", for the imaginary unit, i.\r
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\n" ); document.write( "\n" ); document.write( "\"3%2F%28x%2B1%29%5E2=-2\"\r
\n" ); document.write( "\n" ); document.write( "\"%283%2F%28x%2B1%29%5E2%29%28x%2B1%29%5E2=-2%28x%2B1%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"3=-2%28x%2B1%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%29%5E2=-%283%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B1=0%2B-+sqrt%28-3%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x=-1%2B-+sqrt%28-3%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=-1%2B-+i%2Asqrt%283%2F2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "You can rationalize the denominator if you want.
\n" ); document.write( "\"x=-1%2B-+i%2Asqrt%283%29%28sqrt%282%29%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=-1%2B-+i%281%2F2%29sqrt%286%29%29\"
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