document.write( "Question 1039935: A salesman started walking from office A at 8:30 AM. at the rate of 2.50 kph. He arrived at office B 12 seconds late. Had he started at A at 8:00 AM and walked at 1.50 kph , he would have arrived at B one minute before the appointed time. At what time was he supposed to be at B? \n" ); document.write( "
Algebra.Com's Answer #654690 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A salesman started walking from office A at 8:30 AM. at the rate of 2.50 kph. \n" ); document.write( " He arrived at office B 12 seconds late. \n" ); document.write( " Had he started at A at 8:00 AM and walked at 1.50 kph, he would have arrived at B one minute before the appointed time. \n" ); document.write( " At what time was he supposed to be at B? \n" ); document.write( ": \n" ); document.write( "We are using km/hr, therefore: \n" ); document.write( "Change 12 sec to hrs: 12/3600 = .0033 hrs \n" ); document.write( "Change 1 min to hrs 1/60 = .0167 hrs \n" ); document.write( ": \n" ); document.write( "t = walking time to arrive on time when leaving at 8:30 (2.5 km/hr) \n" ); document.write( "then \n" ); document.write( "(t+.0033) = actual walking time when he was 12 sec late \n" ); document.write( ": \n" ); document.write( "then leaving a half hr earlier \n" ); document.write( "let (t+.5) = walking time to arrive on time when leaving at 8:00 (1.5 km/hr) \n" ); document.write( "then \n" ); document.write( "(t+.5-.0167) = (t+.4833) = actual walking time when he was 1 min early \n" ); document.write( ": \n" ); document.write( "Write a distance equation: dist = speed * time \n" ); document.write( "2.5(t+.0033) = 1.5(t+.4833) (distances are the same) \n" ); document.write( "2.5t + .00825 = 1.5t + .72495 \n" ); document.write( "2.5t - 1.5t = .72495 - .00825 \n" ); document.write( "t = .7167 hrs \n" ); document.write( "Change to min \n" ); document.write( "60 * .7167 = 43 minutes \n" ); document.write( "8:30 + :43 = 9:13 time he is suppose to be there \n" ); document.write( " \n" ); document.write( " |