document.write( "Question 1039888: These probability questions are a duzy for me. Can you help \r
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document.write( "More odds. We can calculate odds if we know the probability. But we can also go the other way. Suppose the odds in favor of an event are 3 to 2.We can interpret this as saying that there are three (equally likely) favorable outcomes and two unfavorable ones. That is a total of five outcomes. So the probability of the event occurring is 3/5. In general, if the odds in favor are p to q, then the probability is p/(p + q). \r
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document.write( " Suppose the odds in favor of an event are 8 to 5. \r
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document.write( "What is the probability that the event will occur? Give the probability as a decimal.\r
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document.write( "(Fill in the blank below and round your answer to 3 decimal places.)\r
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document.write( " The probability that the event will occur is . \r
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document.write( "What is the probability that the event will not occur? Give the probability as a decimal.\r
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document.write( "(Fill in the blank below and round your answer to 3 decimal places.)\r
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document.write( " The probability that the event will not occur is .\r
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Algebra.Com's Answer #654646 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "Let's say we conduct 13 trials. 8 of those trials has the event happen, while the other 5 trials is where the event doesn't happen.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "That's exactly what it means when they say \"odds in favor are 8:5\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In this case, p = 8 and q = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p/(p+q) = 8/(8+5) = 8/13 = 0.615 (use a calculator for the last step)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The probability of the event occurring is 0.615\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract this value from 1 to get the probability of the event not occurring. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1 - 0.615 = 0.385\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The probability of the event NOT occurring is 0.385 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |