document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1039885>Question 1039885</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if a shapes area is 105 square cms and its perimeter is 52 cm what are the measure of the 2 dimensions<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #654644 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=654644\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  if a shapes area is 105 square cms and its perimeter is 52 cm what are the measure of the 2 dimensions<BR>\n" );
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document.write( "The area<BR>\n" );
document.write( "L*W = 105<BR>\n" );
document.write( "L = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=105%2FW ALIGN=MIDDLE  ALT=\"105%2FW\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "The perimeter<BR>\n" );
document.write( "2L + 2W = 52<BR>\n" );
document.write( "simplify, divide by 2<BR>\n" );
document.write( "L + W = 26<BR>\n" );
document.write( "Replace L with <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=105%2FW ALIGN=MIDDLE  ALT=\"105%2FW\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=105%2FW ALIGN=MIDDLE  ALT=\"105%2FW\"   DISABLED_style= \"max-width:90%; height:auto;\" > + W = 26<BR>\n" );
document.write( "multiply by W to get rid of the denominator<BR>\n" );
document.write( "105 + W^2 = 26W<BR>\n" );
document.write( "A quadratic equation<BR>\n" );
document.write( "W^2 - 26W + 105 = 0<BR>\n" );
document.write( "You can use the quadratic formula, but this will factor to:<BR>\n" );
document.write( "(W-21)(W-5) = 0<BR>\n" );
document.write( "Two solutions<BR>\n" );
document.write( "W = 21 is the width, then 5 = the length<BR>\n" );
document.write( "W = 5 is the width, then 21 = the length<BR>\n" );
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document.write( "You can confirm this, find the perimeter with these values </SPAN>\n" );
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