document.write( "Question 1039834: Can someone please help me with this word problem\r
\n" ); document.write( "\n" ); document.write( "From a point on a straight​ road, Chris and Elena ride bicycles in the same direction. Chris rides at 10 mph and Elena rides at 14 mph. In how many hours will they be 30 mi​ apart?
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Algebra.Com's Answer #654574 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+t+\" = time in hrs when Elena ( the faster one ) has
\n" ); document.write( "traveled \"+d+\" miles and Chris ( the slower one ) has traveled
\n" ); document.write( "\"+d+-+30+\" miles.
\n" ); document.write( "Note that they start at the same time and
\n" ); document.write( "from the same place
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\n" ); document.write( "Elena's equation:
\n" ); document.write( "(1) \"+d++=+14t+\"
\n" ); document.write( "Chris's equation:
\n" ); document.write( "(2) \"+d+-+30+=+10t+\"
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\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+14t+-+30+=+10t+\"
\n" ); document.write( "(2) \"+4t+=+30+\"
\n" ); document.write( "(2) \"+t+=+7.5+\"
\n" ); document.write( "They will be 30 mi apart in 7.5 hrs
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\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d++=+14t+\"
\n" ); document.write( "(1) \"+d++=+14%2A7.5+\"
\n" ); document.write( "(1) \"+d+=+105+\" mi
\n" ); document.write( "and
\n" ); document.write( "(2) \"+d+-+30+=+10t+\"
\n" ); document.write( "(2) \"+d+-+30+=+10%2A7.5++\"
\n" ); document.write( "(2) \"+d+=+30+%2B+75+\"
\n" ); document.write( "(2) \"+d+=+105+\" mi
\n" ); document.write( "OK
\n" ); document.write( "( this tells you Elena's distance was 105 mi
\n" ); document.write( "and Chris's distance was 75 mi
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