document.write( "Question 1039827: Thank you all beforehand for helping me out. I really appreciate your time and effort.\r
\n" ); document.write( "\n" ); document.write( "Find the area of triangle ABC if AB = BC = 12 and angle ABC = 120.
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Algebra.Com's Answer #654573 by MathTherapy(10810)\"\" \"About 
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Thank you all beforehand for helping me out. I really appreciate your time and effort.\r
\n" ); document.write( "\n" ); document.write( "Find the area of triangle ABC if AB = BC = 12 and angle ABC = 120.
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You can use: Area of triangle = \r
\n" ); document.write( "\n" ); document.write( "OR\r
\n" ); document.write( "\n" ); document.write( "The altitude that's drawn from ∠ABC to the base (AC) is the SHORTER side of one of the two 30-60-90 special right-triangles that're formed, since it's opposite the smaller of the
\n" ); document.write( "2 acute angles (\"30%5Eo\"). With the hypotenuse being 12, the shorter leg/height = \"matrix%281%2C3%2C+%281%2F2%29+%2A+12%2C+or%2C+6%29\", and the longer leg = \"matrix%281%2C6%2C+shorter%2C+leg%2C+%22%2A%22%2C+sqrt%283%29%2C+or%2C+6+%2A+sqrt%283%29%29\". This means that the base = \"matrix%281%2C3%2C+2+%2A+6sqrt%283%29%2C+or%2C+12sqrt%283%29%29\".
\n" ); document.write( "Therefore, area = \n" ); document.write( "
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