document.write( "Question 1039827: Thank you all beforehand for helping me out. I really appreciate your time and effort.\r
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document.write( "Find the area of triangle ABC if AB = BC = 12 and angle ABC = 120. \n" );
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Algebra.Com's Answer #654568 by josgarithmetic(39799) ![]() You can put this solution on YOUR website! Cut into two right triangles from point B to midpoint of AC.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Look at either of these right triangles. BC is opposite a 90 degree angle, a base leg is opposite a 60 degree angle, and altitude of the isosceles is opposite the 30 degree angle. SPECIAL RIGHT TRIANGLE.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let 6 be the short leg of the special 30-60-90 right triangle. \n" ); document.write( "12 is the length of the hypotenuse. \n" ); document.write( "Let y be altitude or the other leg.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Put attention onto the original isosceles triangle.\r \n" ); document.write( "\n" ); document.write( "You want the area. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |