document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1039811>Question 1039811</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the point (-10,3) un on the terminal side of an angle t. Find cos(t) to 2 decimal places. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #654561 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=654561\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  the point (-10,3) is on the terminal side of an angle t. Find cos(t) to 2 decimal places. <BR>\n" );
document.write( "--------<BR>\n" );
document.write( "x = -10, y = 3<BR>\n" );
document.write( "So, r = sqrt[100+9] = sqrt(109)<BR>\n" );
document.write( "---------------------------<BR>\n" );
document.write( "Ans: cos(t) = x/r = -10/sqrt(109) = -0.96<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "-------------- <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );