document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1039808>Question 1039808</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine the two not given function values in the triple cos(x), sin(x), tan(x)\r<BR>\n" );
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document.write( "cos(x)=-1/3, 3&#960;<x<7&#960;/2\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #654560 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=654560\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Determine the two not given function values in the <BR>\n" );
document.write( "triple cos(t), sin(t), tan(t)<BR>\n" );
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document.write( "cos(t)=-1/3<BR>\n" );
document.write( "Assume t is in QII where x is negative and y is positive::<BR>\n" );
document.write( "By definition cos = x/r<BR>\n" );
document.write( "So x = -1 and r = 3<BR>\n" );
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document.write( "Then y = sqrt[3^2-1^2] sqrt(8) = 2sqrt(2)<BR>\n" );
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document.write( "Ans: sin(t) = y/r = 2srt(2)/3 ; tan(t) = y/x = 2sqrt(2)/(-1) = -sqrt(8)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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