document.write( "Question 1039802: Use log4(7) ≈ 1.4037 and log4 (3) ≈ 0.7925 to approximate the value of each expression. \r
\n" ); document.write( "\n" ); document.write( "log4 (21)
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\n" ); document.write( "log4 (7/12)
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Algebra.Com's Answer #654550 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Use the log rules to say\r
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\n" ); document.write( "\n" ); document.write( "\"log%284%2C%2821%29%29=log%284%2C%283%2A7%29%29\"
\n" ); document.write( "\"log%284%2C%2821%29%29=log%284%2C%283%29%29%2Blog%284%2C%287%29%29\"
\n" ); document.write( "\"log%284%2C%2821%29%29=0.7925%2B1.4037\"
\n" ); document.write( "\"log%284%2C%2821%29%29=2.1962\" (this is approximate)\r
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\n" ); document.write( "\n" ); document.write( "\"log%284%2C%287%2F12%29%29=log%284%2C%287%2F%283%2A4%29%29%29\"
\n" ); document.write( "\"log%284%2C%287%2F12%29%29=log%284%2C%287%29%29-log%284%2C%283%2A4%29%29\"
\n" ); document.write( "\"log%284%2C%287%2F12%29%29=1.4037-%28log%284%2C%283%29%29%2Blog%284%2C%284%29%29%29\"
\n" ); document.write( "\"log%284%2C%287%2F12%29%29=1.4037-%280.7925%2B1%29\"
\n" ); document.write( "\"log%284%2C%287%2F12%29%29=1.4037-1.7925\"
\n" ); document.write( "\"log%284%2C%287%2F12%29%29=-0.3888\" (this is also approximate)
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