document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1039790>Question 1039790</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Need some help with this question please! I know I have to know 0.9 is what isn't defective for (a) and 0.85 for (b), but from there I am lost.\r<BR>\n" );
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document.write( "A stationary store has decided to accept a large shipment of ball-point pens if an inspection of 17 randomly selected pens yields no more than two defective pens.<BR>\n" );
document.write( "(a) Find the probability that this shipment is accepted if 10% of the total shipment is defective.<BR>\n" );
document.write( "(b) Find the probability that this shipment is not accepted if 15% of the total shipment is defective. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #654543 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=654543\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Probability there are 0=0.9^17=0.1668<BR>\n" );
document.write( "there is 1= 17*.9^16*.1, which is 17C1(0,9)^16*(0.1)^1=0.3150<BR>\n" );
document.write( "there are 2=17C2(0.9)^15(0.1)^2=0.2800; 17C2= 17*16/2=136<BR>\n" );
document.write( "The probability is their sum, or 0.7618.  <BR>\n" );
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document.write( "Analogous for 0.85<BR>\n" );
document.write( ".85^17=0.0631<BR>\n" );
document.write( "17(.85^16)(.15^1)=0.1893<BR>\n" );
document.write( "136*(.85^15)(.15^2)=0.2673<BR>\n" );
document.write( "This sum is 0.5197.  It is less, as it should be because there is a higher probability of defective pens and 0,1,2 defects will have a lower probability.<BR>\n" );
document.write( "it is nCk(p)^(n-k)*(1-p)^k </SPAN>\n" );
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