document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1039773>Question 1039773</A>: <I><SPAN STYLE=\"word-break: break-all;\"> this is about a binomial theorem...\r<BR>\n" );
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document.write( "SOLVE: (3x+2y)^10 \r<BR>\n" );
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document.write( "solve it in binomial theorem.Thanks.I really need your help.I ALSO,needs solution or step by step for it.Thanks! :) I hopeyou could help me. :))) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #654531 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=654531\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The 10 terms have coefficients of 10C1, 10C2...10C10<BR>\n" );
document.write( "each term has the coefficient multiplied by (3x) raised to the 10,9,8,7,... and (2y) raised to the 0,1,2,3,4,...<BR>\n" );
document.write( "The total of the exponents will equal 10.  Remember to raise the 3 and the 2 as well.<BR>\n" );
document.write( "(3x+2y)^10=<BR>\n" );
document.write( "10C0(3x)^10*2y^0=3^10*x^10+10*3^9x^9(2y)+45(10C3)*3^8x^8*4y^2(2y)^2+120*3^7x^7(8y^3)+<BR>\n" );
document.write( "210*(3^6)(x^6)(16y^4)+252(3^5)x^5(32y^5)+210(81x^4)(64y^6)+120(27x^3)(128y^7)+45(9x^2)(256y^8)+<BR>\n" );
document.write( "10(3x)(512y^9)+1024y^10\r<BR>\n" );
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document.write( "10Cn((x term)^n*(y term)^(10-n)\r<BR>\n" );
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