document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1039780>Question 1039780</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please I really need help.And it is about BINOMIAL THEOREM.\r<BR>\n" );
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document.write( "SOLVE: (3x+2y)^10\r<BR>\n" );
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document.write( "please I need solution or step by step etc. :))) thank you very much.I hope you can help me. :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #654515 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=654515\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Binomial theorem states<BR>\n" );
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document.write( "(a + b)^n = summation of k from 0 to n of nCk * a^(n-k) * b^k<BR>\n" );
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document.write( "(3x + 2y)^10, where a=3x, b=2y and n=10<BR>\n" );
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document.write( "(3x + 2y)^10 = 10C0(3x)^(10-0)(2y)^0 + 10C1(3x)^(10-1)(2y)^1 + 10C2(3x)^(10-2)(2y)^2 + 10C3(3x)^(10-3)(2y)^3 + 10C4(3x)^(10-4)(2y)^4 + 10C5(3x)^(10-5)(2y)^5 + 10C6(3x)^(10-6)(2y)^6 + 10C7(3x)^(10-7)(2y)^7 + 10C8(3x)^(10-8)(2y)^8 + 10C9(3x)^(10-9)(2y)^9 + 10C10(3x)^(10-10)(2y)^10<BR>\n" );
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document.write( "note that nCk = n! / (k! * (n-k)!)<BR>\n" );
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