document.write( "Question 1039763: newport and vernonville are 112 miles apart.
\n" ); document.write( " a car leaves newport travelling toward vernonville and another car leaves vernonville at the same time travelling to newport. the car leaving newport averages 10 miles per hour more than the other and they meet after 1 hour and 36 minutes. what are the average speed of the cars.
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\n" ); document.write( "\n" ); document.write( "thank you!
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Algebra.Com's Answer #654510 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
You can think of this as one of the cars standing
\n" ); document.write( "still and the other covering the distance between them
\n" ); document.write( "traveling at the sum of their speeds
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\n" ); document.write( "Let \"+s+\" = the speed of the slower car
\n" ); document.write( "\"+s+%2B+10+\" = the speed of the faster car
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\n" ); document.write( "convert \"+36+\" min to hrs
\n" ); document.write( "\"+36%2F60+=+.6+\"
\n" ); document.write( "\"+1+%2B+.6+=+1.6+\" hrs
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\n" ); document.write( "\"+112+=+%28+s+%2B+s+%2B+10+%29%2A1.6+\"
\n" ); document.write( "\"+112+=+%28+2s+%2B+10+%29%2A1.6+\"
\n" ); document.write( "\"+112+=+3.2s+%2B+16+\"
\n" ); document.write( "\"+96+=+3.2s+\"
\n" ); document.write( "\"+s+=+30+\"
\n" ); document.write( "and
\n" ); document.write( "\"+s+%2B+10+=+40+\"
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\n" ); document.write( "Car leaving Vernonville ( slower car ) averages 30 mi/hr
\n" ); document.write( "Car leaving Newport ( faster car averages 40 mi/hr
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\n" ); document.write( "check answer:
\n" ); document.write( "\"+d%5B1%5D+=+30%2A1.6+\"
\n" ); document.write( "\"+d%5B1%5D+=+48+\" mi
\n" ); document.write( "and
\n" ); document.write( "\"+d%5B2%5D+=+40%2A1.6+\"
\n" ); document.write( "\"+d%5B2%5D+=+64+\" mi
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\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+48+%2B+64+\"
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+112+\"
\n" ); document.write( "OK
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