document.write( "Question 1039721: Show all pertinent solution:
\n" ); document.write( "A student can do an encoding job for 10 minutes while another student can do the same job in 20 minutes. How long will it take them to finish the job if they work together?
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Algebra.Com's Answer #654470 by josmiceli(19441)\"\" \"About 
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1st student's rate of working:
\n" ); document.write( "( 1 job ) / ( 10 min )
\n" ); document.write( "2nd student's rate of working:
\n" ); document.write( "( 1 job ) / ( 20 min )
\n" ); document.write( "Let \"+t+\" = time in minutes for them
\n" ); document.write( "to do the job working together
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\n" ); document.write( "Add their rates of working to get their rate
\n" ); document.write( "working together
\n" ); document.write( "\"+1%2F10+%2B+1%2F20+=+1%2Ft+\"
\n" ); document.write( "Multiply both sides by \"+20t+\"
\n" ); document.write( "\"+2t+%2B+t+=+20+\"
\n" ); document.write( "\"+3t+=+20+\"
\n" ); document.write( "\"+t+=+6.667+\" min
\n" ); document.write( "Convert \"+.667+\" min to seconds
\n" ); document.write( "\"+.667%2A60+=+40+\" sec
\n" ); document.write( "-------------------
\n" ); document.write( "Working together, they finish the job
\n" ); document.write( "in 6 min 40 sec
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