document.write( "Question 90161: solve by completing the square\r
\n" ); document.write( "\n" ); document.write( "4x^2+2x-3=0
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Algebra.Com's Answer #65434 by stanbon(75887)\"\" \"About 
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4x^2+2x-3=0
\n" ); document.write( "Rewrite as follows:
\n" ); document.write( "4(x^2+(1/2)x+?) = 3+4*?
\n" ); document.write( "Complete the square on the left and keep the equation balanced.
\n" ); document.write( "4(x^2+(1/2)x+(1/4)^2) = 3 + 4*(1/4)^2
\n" ); document.write( "Factor the left and simplify the right.
\n" ); document.write( "4(x+(1/2))^2 = 3+1/4
\n" ); document.write( "Divide both sides by 4
\n" ); document.write( "(x+(1/2)^2 = 13/16
\n" ); document.write( "Take the square root of both sides.
\n" ); document.write( "(x+(1/2)) = [sqrt13]/4 or x+(1/2) = -[sqrt13]/4
\n" ); document.write( "Rearrange and solve for x:
\n" ); document.write( "x = -(1/2)+[sqrt13]/4 or x = -(1/2)-[sqrt13]/4\r
\n" ); document.write( "\n" ); document.write( "===================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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