document.write( "Question 90161: solve by completing the square\r
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document.write( "4x^2+2x-3=0 \n" );
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Algebra.Com's Answer #65434 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 4x^2+2x-3=0 \n" ); document.write( "Rewrite as follows: \n" ); document.write( "4(x^2+(1/2)x+?) = 3+4*? \n" ); document.write( "Complete the square on the left and keep the equation balanced. \n" ); document.write( "4(x^2+(1/2)x+(1/4)^2) = 3 + 4*(1/4)^2 \n" ); document.write( "Factor the left and simplify the right. \n" ); document.write( "4(x+(1/2))^2 = 3+1/4 \n" ); document.write( "Divide both sides by 4 \n" ); document.write( "(x+(1/2)^2 = 13/16 \n" ); document.write( "Take the square root of both sides. \n" ); document.write( "(x+(1/2)) = [sqrt13]/4 or x+(1/2) = -[sqrt13]/4 \n" ); document.write( "Rearrange and solve for x: \n" ); document.write( "x = -(1/2)+[sqrt13]/4 or x = -(1/2)-[sqrt13]/4\r \n" ); document.write( "\n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |