document.write( "Question 1039572: My problem is:
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document.write( "Walter is 43 years old; his daughter Paulette is 7. In how many years will Paulette be one-third of Walter's age?
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document.write( "I'm afraid I don't know how to set it up. \n" );
document.write( "
Algebra.Com's Answer #654330 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "x = number of years that pass by\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Walter is currently 43 years old. His daughter Paulette is currently 7 years old.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Present Ages \n" ); document.write( "walter = 43 \n" ); document.write( "paulette = 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If we fast foward x years into the future, this means \n" ); document.write( "walter's age = 43+x \n" ); document.write( "paulette's age = 7+x \n" ); document.write( "simply add x to each value\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We want to know when these future ages will be tied together through the following idea \n" ); document.write( "(paulette's age) = (1/3)*(walter's age)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "which is equivalent to saying\r \n" ); document.write( "\n" ); document.write( "(walter's age) = (3)*(paulette's age)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So this means \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(walter's age) = (3)*(paulette's age)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(43+x) = (3)*(7+x) ........ apply substitutions\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "43+x = 3*7+3*x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "43+x = 21 + 3x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "43+x-x = 21 + 3x-x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "43 = 21 + 2x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "43-21 = 21 + 2x-21\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "22 = 2x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x = 22\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x/2 = 22/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 11\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So if 11 years pass by, then Walter will be 43+11 = 54 while Paulette will be 7+11 = 18. Notice how 18*3 = 54. Put another way, 18 is one-third of 54.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the final answer is 11 years. \n" ); document.write( " |