document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1039543>Question 1039543</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm still having trouble with figuring out these formula's to do these problems. I must be missing something! Any help would be greatly appreciated!\r<BR>\n" );
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document.write( "At the time she was hired as a server at the Grumney Family Restaurant, Beth Brigden was told, “You can average $72 a day in tips.” Assume the population of daily tips is normally distributed with a standard deviation of $2.45. Over the first 34 days she was employed at the restaurant, the mean daily amount of her tips was $73.07. At the 0.10 significance level, can Ms. Brigden conclude that her daily tips average more than $72?<BR>\n" );
document.write( "H0: &#956; &#8804; 72 ; H1: &#956; > 72<BR>\n" );
document.write( "Reject H0 if z > 1.28<BR>\n" );
document.write( "Compute the value of the test statistic. (Round your answer to 2 decimal places.)<BR>\n" );
document.write( "What is the p-value? (Round your answer to 4 decimal places.)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #654323 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=654323\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Typically we only use = in stating H0, so I would say that H0 should be<BR>\n" );
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document.write( "H0: x = 72 and H1: x > 72<BR>\n" );
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document.write( "Since H1 contains a strict inequality, we use a one-tailed test<BR>\n" );
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document.write( "Since we are using a 10% significance level, our alpha = 0.10<BR>\n" );
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document.write( "Since the population is normally distributed, we use the standard normal distribution and its z-tables<BR>\n" );
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document.write( "The standard error(SE) is standard deviation / square root of sample size<BR>\n" );
document.write( "SE = 2.45 / 5.83 = 0.42<BR>\n" );
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document.write( "test z-value = (73.07 - 72) / 0.42 = 2.55<BR>\n" );
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document.write( "an alpha of 0.10 corresponds to a z-value of 1.28<BR>\n" );
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document.write( "since our test z-value > 1.28, we reject H0<BR>\n" );
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document.write( "a z-value of 2.55 has a p-value of 0.0054<BR>\n" );
document.write( "note that since the p-value < 0.10, we reject H0<BR>\n" );
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