document.write( "Question 1039507: 2 men and 3 women working 7 hours a day finish a work in 5 days. 4 men and 4 women working 3 hours a day do the same work in 7 days. Find the number of days in which the work is done by 7 men only working 4 hours a day? \n" ); document.write( "
Algebra.Com's Answer #654267 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "If the job is done in 5 days at 7 hours per day, then the whole job is done in 35 hours. Hence, of the job is done in one hour by 2 men and 3 women. So if represents the fraction of the job done by one man in one hour, and represents the fraction of the job done by one woman in one hour, we can say:\r
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\n" ); document.write( "\n" ); document.write( "Using similar analysis:\r
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\n" ); document.write( "\n" ); document.write( "First, solve the 2X2 system. I recommend the elimination method. Multiply the first equation by -20 and the second by 15:\r
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\n" ); document.write( "\n" ); document.write( "Then add\r
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\n" ); document.write( "\n" ); document.write( "Since we want to know about a scenario where only men are working on the job we don't need to solve for .\r
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\n" ); document.write( "\n" ); document.write( "Since one man does of the job in one hour, 7 men do of the job in one hour. Therefore they need to work 20 hours to get the whole job done. If they work 4 hours per day, then it will take 5 days.\r
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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